\( \frac{1}{\log_49}= \)
\( \log_94 \)
\( \log_4\frac{1}{9} \)
\( \frac{1}{\ln8}= \)
\( \log_8e \)
\( -\ln8 \)
\( (\log_7x)^{-1}= \)
\( \log_7\frac{1}{x} \)
\( \log_x7 \)
\( \frac{4a^2}{\log_79}\colon\log_97=16 \)
Halla a a:
\( \pm2 \)
\( 2 \)
\( \frac{\frac{2x}{\log_89}}{\log_98}= \)
\( 2x \)
\( -2x \)
1log49= \frac{1}{\log_49}= log491=
log94 \log_94 log94
1ln8= \frac{1}{\ln8}= ln81=
log8e \log_8e log8e
(log7x)−1= (\log_7x)^{-1}= (log7x)−1=
logx7 \log_x7 logx7
4a2log79 :log97=16 \frac{4a^2}{\log_79}\colon\log_97=16 log794a2:log97=16
±2 \pm2 ±2
2xlog89log98= \frac{\frac{2x}{\log_89}}{\log_98}= log98log892x=
2x 2x 2x