\( (x+3)(x-3)=x^2+x \)
\( x=9 \)
\( x=-9 \)
\( \)\( (x+1)(x-1)(x+1)=x^2+x^3 \)
\( x=0 \)
\( x=-1 \)
\( (x-1)(x+1)(x-2)=-2x^2-x^3 \)
\( x=2 \)
(x+3)(x−3)=x2+x (x+3)(x-3)=x^2+x (x+3)(x−3)=x2+x
x=−9 x=-9 x=−9
(x+1)(x−1)(x+1)=x2+x3 (x+1)(x-1)(x+1)=x^2+x^3 (x+1)(x−1)(x+1)=x2+x3
x=−1 x=-1 x=−1
(x−1)(x+1)(x−2)=−2x2−x3 (x-1)(x+1)(x-2)=-2x^2-x^3 (x−1)(x+1)(x−2)=−2x2−x3
x=2 x=2 x=2