32(12+0−5)=
\( \frac{2}{3}(12+0-5)= \)
\( 5\times3\frac{1}{3}= \)
\( 3\times2\frac{1}{4}= \)
\( 9\times3\frac{8}{9}= \)
\( 9(\frac{1}{3}+\frac{1}{4})= \)
\( (\frac{1}{3}+\frac{5}{12})\times24= \)
\( 10(0.75+1.2)= \)
\( (\frac{1}{3}+\frac{9}{11})\times33= \)
\( x(\frac{1}{3}+\frac{1}{2})= \)
\( \frac{1}{3}(\frac{9}{2}-\frac{3}{4})= \)
\( 5\cdot\big(2\frac{1}{2}+1\frac{1}{6}+\frac{3}{4}\big)= \)